Find the surface area of each figure. Round your answers to the nearest tenth, if necessary.


The surface area of the pyramid is 34.8 in²
Since the figure is a square pyramid, its surface area, A = 4 × area of triangular face + area of square base.
Area of triangular face A' = 1/2bh where
So, A' = 1/2 × 4.3 in × 3 in
A' = 1/2 × 12.9 in²
A' = 6.45 in²
Area of square base A" = L² where L = length of base = 3 in
So, A" = (3 in)²
= 9 in²
Surface area of pyramid, A = 4A' + A"
= 4 × 6.45 in² + 9 in²
= 25.8 in² + 9 in²
= 34.8 in²
So, the surface area of the pyramid is 34.8 in²
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