Question

The water works commission needs to know the mean household usage of water by the residents of a small town in gallons per day. They would like the estimate to have a maximum error of 0.11 gallons. A previous study found that for an average family the standard deviation is 1.8 gallons and the mean is 16.2 gallons per day. If they are using a 98% level of confidence, how large of a sample is required to estimate the mean usage of water? Round your answer up to the next integer.

Answer 1

The sample size required is mathematically given as

n=1454

What is the Margin of error?

Generally, the equation for Margin of error is  mathematically given as

$M=Z_{\alpha/2} > \frac{\sigma}{\sqrt{n}}$

Therefore

$M= 0.11 \leq \frac{ 2.33*1.8}{\sqrt{n}}\\\\\sqrt{n} \leq 38.127$

n=1453.69.

In conclusion, The sample size required is mathematically given as

n=1454

Read more about the sample size

https://brainly.com/question/25894237

#SPJ1