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The surface area of the figure given is of: 61.3 yd².

What is the combined surface area of a figure?

The combined surface area of a figure is the area of each figure.

This figure is composed by:

  • A circle of radius 3 yd.
  • A triangle with base 6 yd and one leg 11.4 yd.

The area of the circle is given as follows:

[tex]A = \pi r^2 = \pi \times 3^2 = 9\pi[/tex]

For the triangle, we need to find it's height, which is the leg of a right triangle, in which one of the sides is 3 and the hypotenuse is 11.4, hence:

h² + 3² = 11.4²

[tex]h = \sqrt{11.4^2 - 3^2}[/tex]

h = 11 yd.

Hence the area of the triangle is:

A = 0.5 x 6 x 11 = 33 yd²

The surface area of the figure is:

9pi + 33 yd² = 61.3 yd².

More can be learned about the surface area of at https://brainly.com/question/21208177

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