Question

A population has a mean of 94 and a standard deviation of 18. A sample of 36 observations will be taken. The probability that the sample mean will be between 89.17 and 101.05 is _____. a. 0.9463 b. 0.4369 c. 0.0094 d. 0.9369

Answer 1

The probability that the sample mean will be between  89.17 and 101.05 is: 0.940091407

What is sample mean?

A sample mean is a data set's average. A data set's central tendency, standard deviation, and variance may all be calculated using the sample mean.

The sample mean may be used to calculate population averages, among other things.

What is the calculation that supports the above answer?

The information given are as follows:
μ = 94,

σ = 18

Where Χ = Sample Mean

hence P (89.17 < X< 101.05) =

P [$\frac{89.17 -94}{18/\sqrt{36} } \leq \frac{X -mu}{sd/\sqrt{xn} } \leq \frac{101.5-94}{18/\sqrt{36} }$]

= P [ -1.61 ≤ Z ≤ 2.5]

= P (Z ≤ -1.61) - P (Z ≤ 2.5)

= NORMSIDST (-1.61) - NORMSDIST (2.5)

= 0.053698928 - 0.993790335

= -0.940091407

Since probability cannot be negative,

The probability that the sample mean will be  between 89.17 and 101.05 is: 0.940091407

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