Mass of Derrick at a height 4.3 m having 2730 joule of energy is 65 Kg.
What is the expression of gravitational potential energy near the earth surface?
- Mathematically, gravitational potential energy near the earth surface= m×g×h
- m= mass of Derrick, g= acceleration due to gravity, h= height at which Derrick present
- Then, mass (m) of Derrick = potential energy/ (g×h)
What is the mass of Derrick, if he gains 2730 joule of energy at 4.3m above the ground?
Mass of Derrick= 2730/(9.8×4.3)
= 65 kg
Thus, we can conclude that the mass of Derrick is 65 Kg.
Learn more about the gravitational potential energy here:
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