Question

SinA=√1-x÷√1+X
Find the value of cosA

Answer 1

The value of cos A is √(1 + x²)/ (1 - x²) /√1 + x

Trigonometric ratios

It is important to note that

sin A = opposite/ hypotenuse

cos A = adjacent/ hypotenuse

Then,

opposite = $\sqrt{1} - x$

Hypotenuse = $\sqrt{1} + x$

Let's find the adjacent side using the Pythagorean theroem

$(\sqrt{1} + x)^2 = (\sqrt{1 -x } )^2 + x^2$

$1 + x^2 = 1 - x^2 + x^2$

$x = \sqrt{\frac{1 + x^2}{1 -x^2} }$

cos A = x/hypotenuse

$cos A = \frac{\sqrt{\frac{1+x^2}{1 -x^2} } }{\sqrt{1} +x}$

cos A = √(1 + x²)/ (1 - x²) /√1 + x

Thus, the value of cos A is √(1 + x²)/ (1 - x²) /√1 + x

Learn more about trigonometric identities here:

https://brainly.com/question/7331447

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