Question

Which of the following linear equations corresponds to the table above?
OA. y=4x-3
OB. y=¹/4x-3
OC. y=¹/4x+3
OD.
y = 4x + 3

Answer 1

$given \: that \: its \: linear \\ m = \frac{15 - 3}{3 - 0} = \frac{12}{3} = 4$

$b = y(0) = 3 \\ y = 4x + 3 \:$

Option D

Answer 2

Answer:

D) y = 4x + 3

Step-by-step explanation:

Equation of line in slope y-intercept form:

   $\sf \boxed{\bf y = mx +b}$

Here, m is the slope and b is y intercept.

At y intercept, x = 0

         From the table, y intercept  = 3

Choose any two points from the table to find the slope.

(0 ,3)  & (3,15)

$\sf \boxed{\bf Slope =\dfrac{y_2-y_1}{x_2-x_1}}$

           $\sf =\dfrac{15-3}{3-0}\\\\=\dfrac{12}{3}\\\\=4$

m = 4 ; b = 3

 Equation of line:

                 y = 4x  + 3