Respuesta :

Step-by-step explanation:

so ,

Question 6 :-

5 × (3+4) - 4

first solve the Bracket ......

5 × (7) - 4

after multiplication ......

35 - 4

= 31

so , Answer is 1st one ....

Question 7 :-

8 + 1/2 × (6-2) -1

so , here also solve the Bracket first .....

8 + 1/2 × (4) - 1

after multiplication .....

8 + 2 - 1

after + and - .......

10 - 1

= 9 .......

so , Answer is 2nd one .....

Ver imagen ouff2003

Answer:

Q6: 5 times the sum of 3 and 4, then subtract 4.

Q7: Add 8 to half the difference of 6 and 2, then subtract 1.

Step-by-step explanation:

Question 6:

[tex]5 \times (3 + 4) -4[/tex]

• First of all, we can see that 5 is being multiplied by something, so we can say "5 times...".

• Next we see that the 5 was being multiplied by the sum of 3 and 4, so we can combinedly say "5 times the sum of 3 and 4...".

• And finally, we see that 4 is taken away from the result. Therefore we can say " 5 times the sum of 3 and 4, then subtract 4".

Question 7:

[tex]8 + \frac{1}{2} \times (6-2) -1[/tex]

• Firstly, we can see that 8 is being added to something, so we can say "Add 8...".

• Next, we see that 8 was being added to [tex]\bf \frac{1}{2}[/tex] of something, so we can combinedly say "Add 8 to half of...".

• Then we see that the difference (i.e., result of subtraction) of 6 and 2 was being halved. Therefore we say "Add 8 to half of the difference of 6 and 2...".

• Finally, we can see that 1 is subtracted from the result. Therefore, we can say "Add 8 to half of the difference of 6 and 2, then subtract 1".

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