5th grade Pre algebra. Pls help I’m rlly stuck will give brainliest c:

Step-by-step explanation:
so ,
Question 6 :-
5 × (3+4) - 4
first solve the Bracket ......
5 × (7) - 4
after multiplication ......
35 - 4
= 31
so , Answer is 1st one ....
Question 7 :-
8 + 1/2 × (6-2) -1
so , here also solve the Bracket first .....
8 + 1/2 × (4) - 1
after multiplication .....
8 + 2 - 1
after + and - .......
10 - 1
= 9 .......
so , Answer is 2nd one .....
Answer:
Q6: 5 times the sum of 3 and 4, then subtract 4.
Q7: Add 8 to half the difference of 6 and 2, then subtract 1.
Step-by-step explanation:
[tex]5 \times (3 + 4) -4[/tex]
• First of all, we can see that 5 is being multiplied by something, so we can say "5 times...".
• Next we see that the 5 was being multiplied by the sum of 3 and 4, so we can combinedly say "5 times the sum of 3 and 4...".
• And finally, we see that 4 is taken away from the result. Therefore we can say " 5 times the sum of 3 and 4, then subtract 4".
[tex]8 + \frac{1}{2} \times (6-2) -1[/tex]
• Firstly, we can see that 8 is being added to something, so we can say "Add 8...".
• Next, we see that 8 was being added to [tex]\bf \frac{1}{2}[/tex] of something, so we can combinedly say "Add 8 to half of...".
• Then we see that the difference (i.e., result of subtraction) of 6 and 2 was being halved. Therefore we say "Add 8 to half of the difference of 6 and 2...".
• Finally, we can see that 1 is subtracted from the result. Therefore, we can say "Add 8 to half of the difference of 6 and 2, then subtract 1".