The unknown temperature is 64°C
Given,
Resistance at ice point,R[tex]_{0}[/tex] =5.2Ω,
Resistance at steam point,R[tex]_{100}[/tex] = 5.7Ω,
Resistance when dip in unknow, R[tex]_{t}[/tex] = 5.5Ω,
R[tex]_{100}[/tex] = R[tex]_{0}[/tex] (1+α100)
α = R[tex]_{100}[/tex]-R[tex]_{0}[/tex] / R[tex]_{0}[/tex]×100
α = 0.00096 = 9×[tex]10^{-4}[/tex]°C[tex]^{-1}[/tex]
Let the temperature of hot bath = t°C
R[tex]_{t}[/tex] = R[tex]_{0}[/tex](1+αt)
t = R[tex]_{t}[/tex]- R[tex]_{0}[/tex] / R[tex]_{0}[/tex] α
t = 0.3 / 0.00468
t = 64°C
The unknown temperature is 64°C.
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