Question

Someone help quickly pls :(

Assignment
Practice finding solutions to systems of equations using
substitution.
The value of x in this system of equations is 1.
3x + y = 9
y=-4x+10
1. Substitute the value of y in the first equation:
2. Combine like terms:
3. Apply the subtraction property of equality:
4. Apply the division property of equality:
What is the value of y?
y=
3x + (-4x+10) = 9
-x+10=9
-x=-1
x=1

Answer 1

Answer:

y = 6

Step-by-step explanation:

Solving system of linear equation using substitution method:

   3x + y = 9 ---------------(I)

          y = -4x + 10 -----------------(II)

Substitute y = -4x + 10 in equation (I)

  3x - 4x + 10 = 9

Combine like terms,

        -x + 10  = 9

Subtract 10 from both sides. (subtraction property of equality)

               -x  = 9 - 10

              -x = -1

Divide both sides by (-1).  {Division property of equality}

              $\sf \dfrac{-x}{-1}=\dfrac{-1}{-1}\\\\ \boxed{x = 1}$

Now, substitute x = 1 in equation (II) and find the value of y.

        y = -4*1 + 10

          = -4 + 10

       $\sf \boxed{\bf y = 6}$