Answer:
[tex]\sf y =\dfrac{3}{2}x+2[/tex]
Step-by-step explanation:
Equation of line:
Pick any two points on the line.
(0,2) and (2 , 5)
(0,2) ⇒ x₁ = 0 & y₁ = 2
(2,5) ; x₂ = 5 & y₂ = 5
[tex]\sf \boxed{\bf Slope =\dfrac{y_2-y_1}{x_2-x_1}}[/tex]
[tex]\sf =\dfrac{5-2}{2-0}\\\\=\dfrac{3}{2}[/tex]
Equation of line in point slope form:
[tex]\sf y - y_1 =m(x -x_1)[/tex]
Point(0 ,2) and m = 3/2
[tex]\sf y - 2 = \dfrac{3}{2}(x -0)\\\\ y - 2 = \dfrac{3}{2}x\\\\[/tex]
Equation of line in slope y-intercept form:
[tex]\sf y =\dfrac{3}{2}x+2[/tex]
