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√₂º · Va This can be transformed into a basic integral by letting Consider the indefinite integral U= x' +9 ✓ and du = 7x6 ✓dx · √x + 9 dx: Performing the substitution yields the integral​

º Va This can be transformed into a basic integral by letting Consider the indefinite integral U x 9 and du 7x6 dx x 9 dx Performing the substitution yields the class=

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Answer:

[tex]u = x^{7} +8[/tex]     [tex]du = 7x^{6} dx[/tex]   result is [tex]\frac{1}{7} \sqrt[4]{u}[/tex]

Step-by-step explanation:

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