Using the simple interest formula, it is found that the APR for the loan is of 4.472%.
Simple interest is used when there is a single compounding per time period.
The amount of money after t years in is modeled by:
[tex]A(t) = A(0)(1 + rt)[/tex]
In which:
The parameters for this problem are:
A(t) = 6 x 511.18 = 3067.08, A(0) = 3000, t = 0.5.
We solve the equation for r to find the APR.
[tex]A(t) = A(0)(1 + rt)[/tex]
[tex]3067.08 = 3000(1 + 0.5r)[/tex]
[tex]1 + 0.5r = \frac{3067.08}{3000}[/tex]
1 + 0.5r = 1.02236
r = (1.02236 - 1)/0.5
r = 0.04472.
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