What is the osmotic pressure of a solution made from 12.5 g of CaCl2 in enough water to make 500 mL, if CaCl2 is 78.5% dissociated at 30oC

Respuesta :

The osmotic pressure of a solution made from 12.5 g of CaCl2 in enough water to make 500 mL, if CaCl2 is 78.5% dissociated at 30oC is 167.087 atm

Define osmotic pressure:-

Osmotic pressure and osmosis are connected. Osmosis is the passage of a solvent through a semipermeable membrane into a solution. The pressure that halts the osmosis process is known as osmotic pressure. Osmotic pressure is a collective attribute of material because its value is determined by the solute's concentration rather than its chemical composition.

The formula used to calculate Osmotic Pressure is:-

π = M x R x T x i

Where;

π =osmotic pressure (in atm)

M=molar concentration (in mol/L)

  =(given mass/molar mass)/volume=(12.5g /111.0)/(500/1000)

  =0.224 mol/L

R=Universal gas constant (0.08206 L.atm/mol.K)

T=absolute temperature (in K) = 30.C + 273 = 303 K

i= van't Hoff factor of solute =3

using the formula and  substituting values;

π=0.224 x 0.08206 x 303 x 3

   = 167.087 atm

The osmotic pressure is 167.087 atm

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