The rate of change of the current in the larger inductor is 0.3mA/s.
To find the answer, we need to know about the relation between the emf and inductance.
What's the mathematical expression to find the emf in term of inductance?
- Mathematically, emf induced across an inductor= L× (dI/dt)
- L= inductance and dI/dt = rate of change of current
What is the rate of change of current in 4.5 mH when when the total emf of the combination is 16 V?
- As both the inductors are connected in parallel, so emf of the combination remains same across each inductor.
- Emf induced in 4.5mH = 16 V
- dI/dt = 4.5mH / 16 = 0.3 mA/s
Thus, we can conclude that the rate of change of the current in the larger inductor is 0.3mA/s.
Learn more about the induced current here:
brainly.com/question/20077104
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