Question

A 6.0 mH inductor is in a circuit. At the instant the current is 5.0 A and its rate of change is 200 A/s, the rate with which the energy stored in the inductor is increasing is:

Answer 1

The rate with which the energy stored in the inductor is increasing at 6 Joule/s.

To find the answer, we need to know about the rate of change of energy in inductor.

What's the rate of change of energy of inductor?

• The energy stored in inductor (E)=(1/2)× L× I²
• The rate of change of energy (dE/dt) = L×I×(dI/dt)

What's the rate of energy increased in the inductor, if rate of increasing current, L and I are respectively 200A/s, 6mH and 5 A respectively?

• Here , dI/dt = 200A/s, L=6mH, I = 5 A
• Rate of energy increased= 6mH×5×200

= 6 Joule/s

Thus, we can conclude that the rate of increasing energy is 6 Joule/s.

Learn more about the energy stored in inductor here:

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