V₂O₅ (s) + 2H₂ (g) → V₂O₃ (s) + 2H₂O(l) is the balanced chemical equation for the reaction of solid vanadium(V) oxide with hydrogen gas to form solid vanadium(III) oxide and liquid water.
The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.
The word based equation is
Vanadium(V) oxide + Hydrogen gas → Vanadium (III) oxide + Water
Now write the chemical equation
V₂O₅ (s) + 2H₂ (g) → V₂O₃ (s) + 2H₂O(l)
Reactant side Product side
V = 2 V = 2
O = 5 O = 5
H = 4 H = 4
We can see that the number of atoms on reactant side is equal to the number of atoms on product side. So the given equation is balanced.
Thus from the above conclusion we can say that V₂O₅ (s) + 2H₂ (g) → V₂O₃ (s) + 2H₂O(l) is the balanced chemical equation for the reaction of solid vanadium(V) oxide with hydrogen gas to form solid vanadium(III) oxide and liquid water.
Learn more about the Balanced chemical equation here: https://brainly.com/question/15355912
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