Question

A car heading north collides at an intersection with a truck of the same mass as the car heading east. If they lock together and travel at 28 m/s at 46° north of east just after the collision, how fast was the car initially traveling? assume that any other unbalanced forces are negligible.

Answer 1

Answer: A car heading north collides at an intersection with a truck of the same mass as the car heading east. If they lock together and travel at 28 m/s at 46° north of east just after the collision, then the car initially traveling with a velocity of 40.28m/s.

Explanation: To find the answer, we need to know more about the Perfectly inelastic collision.

What is perfectly inelastic collision?

• Collision is an interaction between two bodies due to which the individual momenta of the colliding bodies are changed, but the total momentum remains constant.
• If the colliding bodies stick together after collision, then it is called perfectly inelastic collision.
• here, the coefficient of restitution will be equal to 0.
• For, inelastic collision, the momentum is conserved, but the energy is not conserved.

How to solve the problem?

• let's write the conservation equation of momentum as,

               $m_1v_1+0=(m_1+m_2)v_2$

• We have to find the value of initial velocity v1,

               $mv_1=(m+m)28 sin46\\v_1=2*28*0.719=40.28 m/s$

Thus, we can conclude that, the initial velocity of the car will be 40.28m/s.

Learn more about the perfectly inelastic collision here:

https://brainly.com/question/28045028

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