Question

An 800-N box is pushed up an inclined plane. The plane is 4.0 m long and 2.0 m high. If it requires 3200 J of work to get the box to the top of the plane, what was the magnitude of the average friction force on the box? Group of answer choices 400 N 0 N Non-zero, but less than 400 N Greater than 400 N

Answer 1

The magnitude of the average friction force on the box is 400 N

What is energy conservation?

It is the principle by which the total energy remains constant in a system that is not subject to external influence.

It states that energy can neither be created nor be destroyed, It may be transformed from one form to another.

Here,

length of the plane, d = 4 m

height of the plane, h = 2 m

work done total, w = 3200 J

kinetic energy on top, KE = 0

Potential energy on top,

PE = weight x height

PE = 800 *2

PE = 1600 J

Now,

Total work done = KE + PE + W (friction)

W (friction) = 3200 - 1600

W (friction)  = 1600 J

W (friction) = F (friction) x d

F (friction) = 1600 / 4

F (friction) = 400 N

Hence,

The magnitude of the average friction force on the box is 400 N

option A is correct

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