Question

does anyone know how to this problem? 4 * log3 + log2 writing it as a single logarithm

Please Help!

Answer 1

4*log3 = log(3^4)
log(3^4) + log4 = log(81*4) = log324
(You know, loga + logb = logab)

Answer 2

Good idea to look up "Rules of Logarithms" and commit them to memory.  You'll need two such rules here.  One rule looks like this:

a log b = log b^a (a becomes the exponent of the argument b)

Apply this rule to the given 4 log 3.

The other rule has to do with products:  log a + log b = log a*b.

Apply this rule after you've followed my previous suggestion.