Question

Suppose there is a triangle with sides a, b, and c and angles A, B, and C. Using the known given information below and the law of cosines, what is the measure of angle C? Round your answer to the nearest whole number, if necessary.

A=29
C=24
B=101

Answer 1

The measure of angle C is obtained as 35 degrees

What is the angle C?

Give that;

b^2 = a^2 + c^2 - 2ac Cos B

a = 29

c = 24

B = 101 degrees

b^2 = (29)^2 + (24)^2 - [2 * 29 * 24 cos 101]

b^2 = 841 + 576 + 266

b = 41 cm

Now;

b/sinB = c/sinC

bsinC = csinB

sinC = csinB/b

sinC =  24 * sin 101/41

C = sin-1(24 * sin 101/41)

C = 35 degrees

Learn more about cosine rule;https://brainly.com/question/20839703

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