please help with question #2
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The Ksp of the solution is 3.2 * 10^-8.
The Ksp is called the solubility product . We know it to be the equilibrium constant that shows the extent to which a substance is dissolved in solution.
Now given that;
CaF2(s) ⇔ Ca^2+(aq) + 2F^-(aq)
Ksp = [ Ca^2+] [F^-]^2
Ksp = [0.002] [0.004]^2
Ksp = 3.2 * 10^-8
Learn more about Ksp:https://brainly.com/question/27132799
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