Question

A sample of gas has its number of molecules quadrupled, its Kelvin temperature doubled, and its volume tripled. By what factor has the new pressure changed relative to the original pressure

Answer 1

The new pressure changed relative to the original by a factor of 8/3.

What is the change in the pressure?

Using the ideal gas equation;

PV = nRT

P = pressure

V = volume

n = number of moles

R = gas constant

T = temperature

P1 = nRT/V

P2 = 4n * R * 2T/3V

Hence;

P2/P1 = 4n * R * 2T/3V ÷  nRT/V

P2/P1 = 4n * R * 2T/3V * V/nRT

P2/P1 =4 * 2/3

= 8/3

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