The temperature of the filament is 2500 K when the bulb is switched on. The diameter of the filament is 0.1 mm and it is made of metal of emissivity 0.35. If the emissive power is 40 W find the length of the filament.​

Respuesta :

The length of the filament is 0.2 m.

To find the answer, we need to know about the Stefan - Boltzmann law.

What's Stefan - Boltzmann law?

  • It states that the intensity of power radiated from a body is propertional to the fourth power of temperature of the object.
  • Mathematically, I= e×σ×T⁴
  • I= intensity, e= emissivity, σ= a constant with value 5.67×10^(-8) W/(m²K⁴), T= temperature
  • As intensity= power/area, so power= area ×e×σ×T⁴

What's the length of the filament having diameter 0.1 mm, temperature 2500K, emissivity 0.35 and radiating power of 40W?

  • Here, e= 0.35, T= 2500K, power= 40W
  • If L= length of the filament, its area = (2πd/2)L= πdL
  • So, power= π×d×L ×e×σ×T⁴

L= power/(π×d×e×σ×T⁴)

= 40/(π×0.0001×0.35×5.67×10^(-8)×2500⁴)

= 0.2m

Thus, we can conclude that the length of the filament is 0.2 m.

Learn more about the Stefan - Boltzmann law here:

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