Question

If 5.00 L of argon gas is at 0.460 atm and -123°C, what is the volume at STP?

Answer 1

Answer:

4.27 L

Explanation:

STP = 0 C   and   1 atm  

P1V1/T1   = P2V2/T2       where T is in Kelvin

P1 V1 / T1   *T2/P2   = V2

.469 * 5 / ( 273.15-123)  *  273.15/1   = V2 = 4.27 L