Respuesta :
[tex]2x - 15 \leqslant 5 \\ 2x \leqslant 20 \\ x \leqslant 10[/tex]
Interval Notation: x ε ( -∞ , 10 ]
[tex]\Huge\boxed{x\leq10}[/tex]
To solve for [tex]x[/tex], you need to isolate it on one side of the equation.
Start by adding [tex]15[/tex] to both sides.
[tex]\begin{aligned}2x-15+15&\leq5+15\\2x&\leq20\end{aligned}[/tex]
Now, divide both sides by [tex]2[/tex] for the final answer.
[tex]\begin{aligned}\frac{2x}{2}&\leq\frac{20}{2}\\x&\leq10\end{aligned}[/tex]