Question

For the reaction: N2(g) + H2(g) → NH3(g)
If the rate of decrease of N2 is -0.11M/s what is the rate of increase of NH3?

I know I must first balance the equation, to which I get: N2+3H2 -> 2NH3

Where do I go from here? Please explain step by step

Answer 1

The rate of increase of NH3 is 0.22M/s.

What is the balanced equation of the reaction?

The balanced equation of the reaction is given below:

• N2(g) + 3 H2(g) → 2 NH3(g)

The rate of decrease of N2 is half the rate of increase of NH3.

Rate of decrease of N2 = -0.11 M/s

Rate of increase of NH3 = 2 × +0.11 M/s = 0.22M/s.

In conclusion, the rate of formation of products is dependent on the rate of disappearance of reactants.

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