Question

vanillin is a flavoring agent in vanilla it has a mass percent composition of 61.15% c,5.3%H,31.55% o determine the empirical formula and molecular formula if molecular mass of vanillin is 152.15%g/mol

Answer 1

The empirical and molecular formulas will be  $C_5H_5O_2$ and  $C_1_0H_1_0O_4$ respectively.

Empirical and molecular formula

The compound contains C, H, and O.

C = 61.15/12 = 5.0958

H = 5.3/1 = 5.3

O = 31.55/16 = 1.9719

Divide by the smallest

C = 2.6

H = 2.7

O = 1

Thus, the empirical formula is $C_5H_5O_2$

Empirical formula mass = (12x5) + (1x5) + 16x2 = 97

n = 152.15/97 = 2

The molecular formula is $C_1_0H_1_0O_4$

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