Question

In the above reaction, how many moles of nitrogen gas can theoretically be produced by 2.177 moles of N2H4, assuming there is an excess of N2O4?

Answer 1

The number of moles of nitrogen that can be produced theoretically will be 3.2655 moles.

Stoichiometric problem

The equation of the reaction is as follows:

$2N_2H_4 + N_2O_4 --- > 3N_2 + 4H_2O$

The mole ratio of $N_2H_4$ reacted to that of $N_2$ produced is 2:3.

Thus, with 2.177 moles of  $N_2H_4$ , the theoretical number of moles of $N_2$ can be calaculated as:

                         3/2 x 2.177 = 3.2655 moles

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