Question

Use the quadratic formula to find both solutions to the quadratic equation
given below.

Answer 1

The solution of the equation are $x = \frac{7 + \sqrt{61}}{6}$ and $x = \frac{7 - \sqrt{61}}{6}$

How to determine the solution?

The equation is given as:

3x^2 - 7x- 1 = 0

The quadratic equation is represented as:

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

So, we have:

$x = \frac{7 \pm \sqrt{(-7)^2 - 4 *3 *-1}}{2*3}$

Evaluate the expression

$x = \frac{7 \pm \sqrt{61}}{6}$

Expand

$x = \frac{7 + \sqrt{61}}{6}$ and $x = \frac{7 - \sqrt{61}}{6}$

Hence, the solution of the equation are $x = \frac{7 + \sqrt{61}}{6}$ and $x = \frac{7 - \sqrt{61}}{6}$

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