Betty and Jane have the same number of coins. Betty
sorts her coins in groups of 6, with no coins left over.
Jane sorts her coins in groups of 8, with no coins left
over. What is the least possible number of coins that each
of them has?

Respuesta :

Using the least common multiple, it is found that the least possible number of coins that each of them has is of 24.

What is the least possible number of coins that they have?

They have the same number of coins, with Betty sorting the coins in groups of 6 and Jane sorting the coins in groups of 8, and none of them having coins remaining.

Thus, the least possible number of coins they have is the least common multiple of 6 and 8, found factoring both these numbers into prime factors, as is done below:

6 - 8|2

3 - 4|2

3 - 2|2

3 - 1|3

1

Hence the least common multiple of 6 and 8 is given by:

lcm(6,8) = 2 x 2 x 2 x 3 = 2³ x 3 = 24.

Thus, it is found that the least possible number of coins that each of them has is of 24.

More can be learned about the least common multiple at https://brainly.com/question/24873870

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