Question

There are currently 19 frogs in a (large pond. the frog population grows exponentially, tripling every 8 days. how long will it take (in days for there to be 290 frogs in the pond?

Answer 1

Population growth factor = 3^(days/8)
Day zero 19 Frogs
Population = 19*3^(days / 8)
We are to calculate when population = 290
290 = 19*3^(days / 8)
290 / 19 = 3^(days/8)
log(290/19) = (days/8) * log(3)
log (15.2631578947) / log (3) = days/8
1.1836443969 / 0.4771212547 = days/8
2.4808041672 = days / 8
days = 8 * 2.4808041672
days =  19.8464333372 days