Question

If body fat has a density of 0.93 g/mL and 3.7 L of fat is removed, how many pounds of fat were removed from the patient?

Answer 1

Data:

density (d) = 0.93 g/mL
volume (v) = 3.7 L → 3700mL
mass (m) = ? (pounds)

Formula:

$d = \frac{m}{v}$

Solving:


$d = \frac{m}{v}$
$0.93\:g/\diagup\!\!\!\!\!m\diagup\!\!\!\!\!L = \frac{m}{3700\:\diagup\!\!\!\!\!m\diagup\!\!\!\!\!L}$
$m = 0.93*3700$
$m = 3441\:g\to\:\boxed{m\approx7.58\:pounds}\end{array}}\qquad\quad\checkmark$

Answer:
$\underline{7.58\:pounds\:of\:fat\:were\:removed\:from\:the\:patient}$