Respuesta :
[tex]\bf \begin{array}{cccccclllll}
\textit{something}&&\textit{varies directly to}&&\textit{something else}\\ \quad \\
\textit{something}&=&{{ \textit{some value}}}&\cdot &\textit{something else}\\ \quad \\
y&=&{{ k}}&\cdot&x
&& y={{ k }}x
\end{array}
\\ \quad \\
\textit{we know that, when}
\begin{cases}
y=-3\\
x=5
\end{cases}\implies y=kx\implies (-3)=k(5)[/tex]
solve for "k", to find the "constant of variation",
then plug it back in the y = kx, to get the equation
now
what's is y when x = -1?
well, just plug that in the equation with the found "k" value,
to get "y" :)
solve for "k", to find the "constant of variation",
then plug it back in the y = kx, to get the equation
now
what's is y when x = -1?
well, just plug that in the equation with the found "k" value,
to get "y" :)
Answer:
The value of y at x=-1 is 3/5.
Step-by-step explanation:
It is given that y varies directly with x. It means y is directly proportional to x.
[tex]y\propto x[/tex]
[tex]y=kx[/tex] .... (1)
where, k is constant of proportionality.
It is given that y=-3 when x=5.
Substitute y=-3 and x=5 in equation (1).
[tex]-3=k(5)[/tex]
[tex]-\frac{3}{5}=k[/tex]
The value of k is -3/5.
[tex]y=-\frac{3}{5}x[/tex] .... (2)
We need to find the value of y when x=-1.
Substitute x=-1 in equation (2).
[tex]y=-\frac{3}{5}(-1)[/tex]
[tex]y=\frac{3}{5}[/tex]
Therefore the value of y at x=-1 is 3/5.