If there are two real solutions to the equation x^2 + 4x + c = 0, which is a possible value of c?

A. 20

B. 17

C. -5

D. 16

Respuesta :

[tex]\bf \begin{array}{lcccllll} 1x^2 &+ 4x &+ c\\ \uparrow &\uparrow &\uparrow \\ a&b&c \end{array}\qquad discriminant\implies b^2-4ac \\ \quad \\ \textit{if the discriminant is} \begin{cases} positive\to &\textit{two solutions}\\ 0\to &\textit{one solution}\\ negative\to &\textit{no solution} \end{cases}[/tex]

so.. check your "c" choices, to see which one gives you a positive discriminant
C Appears To Be An Answer Choice