Question

Using a table of standard electrode potentials, label each of the following statements as completely
true or false.
A) Cu²+ can oxidize H2, and Fe can reduce Mn²+
B) Ni²+ can oxidize Cu²+, and Fe²+ can reduce H+
C) Fe²+ can oxidize H₂, and Fe²+ can reduce Au³+.
D) Br₂ can oxidize Ni, and H₂ can reduce Mn²+
E) H* can oxidize Fe, and Ni can reduce Br₂

Answer 1

Answer: B and E are True

Explanation:

Because Fe has a higher oxidation potential than H2, H+ can oxidize it.

$\begin{array}{llllll}\mathrm{Fe} & \rightarrow & \mathrm{Fe}^{2+} & +2 \mathrm{e}- & \mathrm{E}^{0}=0.44 \mathrm{~V} \\ \mathrm{H} & \rightarrow & \mathrm{H}^{+} & + & \mathrm{e}^{-} & \mathrm{E}^{0}=0 \mathrm{~V}\end{array}$

Ni can reduce Br2 because the reduction potential of Ni is more than Br2.

$\mathrm{Ni}^{2+}+2 \mathrm{e}^{-} \rightarrow \mathrm{Ni}^{-} \quad \mathrm{E}^{0}=-0.25 \mathrm{~V}\\2 \mathrm{Br}^{-} \quad \rightarrow \mathrm{Br}_{2}+2 \mathrm{e}^{-} \quad \mathrm{E}^{0}=-1.087 \mathrm{~V}$