Question

Find the area of the trapezoid. TOP 11ft, RIGHT4√3ft , BOTTOM 15ft ,LEFT 8ft

Answer 1

Answer:

$52\sqrt{3} ft^{2}$

Step-by-step explanation:

Please refer to the attached picture.

First we will find the area of rectangle BCDE.

Area of Rectangle = Length x Breadth = DE x CD

= 11 x $4\sqrt{3}$

$=44\sqrt{3} ft^{2}$

Next we will find Area of Triangle ABE.

Area of Triangle = 0.5 x Base x Height

$0.5*4*4\sqrt{3} \\=8\sqrt{3} ft^{2}$

Area of Trapezoid = Area of Rectangle + Area of Triangle

$=44\sqrt{3} +8\sqrt{3} \\=52\sqrt{3} ft^{2}$

Answer 2

Answer:

A = 52$\sqrt{3}$ ft² ≈ 90.1 ft²

Step-by-step explanation:

the area (A) of a trapezoid is calculated as

A = $\frac{1}{2}$ h (b₁ + b₂ )

where h is the perpendicular height and b₁ , b₂ the parallel bases

here h = 4$\sqrt{3}$ , b₁ = 15 , b₂ = 11 , then

A = $\frac{1}{2}$ × 4$\sqrt{3}$ × (15 + 11)

   = 2$\sqrt{3}$ × 26

   = 52$\sqrt{3}$ ft²

   ≈ 90.1 ft² ( to the nearest tenth )