Calculate how many grams of the product form when 16.7 g of calcium metal completely reacts. Assume that there is more than enough of the chlorine gas.

Ca(s) + Cl2(g) → CaCl2(s)

Respuesta :

39.96 g product form when 16.7 g of calcium metal completely reacts.

What is the stoichiometric process?

Stoichiometry is a section of chemistry that involves using relationships between reactants and/or products in a chemical reaction to determine desired quantitative data.

Equation:

[tex]Ca(s) + Cl_2(g)[/tex] → [tex]CaCl_2(s)[/tex]

In this case, for the undergoing reaction, we can compute the grams of the formed calcium chloride by noticing the 1:1 molar ratio between calcium and it (stoichiometric coefficients) and using their molar mass of 40 g/mol and 111 g/mol by using the following stoichiometric process:

[tex]m_{ca_C_l_2}[/tex]= 16.7 g Ca x [tex]\frac{1 mol \;of \;Ca}{40g Ca}[/tex] x [tex]\frac{1 mol \;of \;CaCl_2}{1 mol \;Ca}[/tex] x [tex]\frac{111g of \;CaCl_2}{1 mol \;CaCl_2}[/tex]

[tex]m_{ca_C_l_2}[/tex] = 39.96 g

Hence, 39.96 g product form when 16.7 g of calcium metal completely reacts.

Learn more about the stoichiometric process here:

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