Question

PLEASE HELP FAST! What is the percent yield if 0.856 g of NO is actually obtained in the lab during the following reaction: 4NH3 + 5O2 --> 4NO + 6H2O . 6.3 g of Ammonia was reacted with 1.8 g of Oxygen?


Options:

A. 20.1%

B. 53.5%

C. 89.4%

D. 63.4%

Answer 1

The percent yield of the reaction is 63.4%; option D

What is percent yield?

Percent yield of a reaction is given as:

• Percent yield = actual yield/expected yield * 100 %

Actual yield of the reaction = 0.856 g

Expected yield = 1.8/32 * 4/5 * 30 = 1.35 g

Percent yield = 0.856/1.35 * 100 % = 63.4 %

Therefore, the percent yield is 63.4%.

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