Question

Which of the following is a solution to the equation x$x^{2}$– 6x + 5 = 0?

Answer 1

Answer:

$\huge\boxed{\sf x =5 \ \ \ OR \ \ \ x = 1}$

Step-by-step explanation:

Given equation:

$x^2-6x+5=0$

Using mid-term break formula

• Multiply -5 and -1 gives +5 (side term) and adding them gives -6 (mid term).
• So, split -6 into -5 and -1

$x^2-5x-x+5=0\\\\Take \ common\\\\x(x-5)-1(x-5)=0\\\\Take \ (x-5) \ common\\\\(x-5)(x-1)=0$

Either,

x - 5 = 0         OR         x - 1 = 0

x = 5           OR       x = 1

$\rule[225]{225}{2}$