Question

1 peasant changed rabbits to hens and 2 rabbits were equal to 3 hens, each hen produced the eggs that were equal to ⅓ of the total number of hens, the peasant sold the eggs, 9 eggs will cost as many pennies as each hen that produced the eggs and totally he got 72 pennies so how many hens and how many rabbits he had?

Answer 1

The peasant had 28 hens and 42 rabbits

How to determine the number of hens and rabbits?

Represent hens with h, eggs with e and rabbits with r.

So, we have:

2r = 3h

e = 1/3h

Make h the subject in e = 1/3h

h = 3e

He got 72 pennies.

So, we have:

r + h = 72

Multiply through by 2

2r + 2h = 144

Substitute 2r = 3h in 2r + 2h = 144

3h + 2h = 144

Evaluate the sum

5h = 144

Divide by 5

h = 28.8

Remove decimal

h = 28

Recall that:

2r = 3h

So, we have:

2r= 3 * 28

Divide by 2

r = 3 * 14

Evaluate the product

r = 42

Hence, the peasant had 28 hens and 42 rabbits

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