Question

What is the quotient startfraction negative 8 a superscript 8 baseline b superscript negative 2 baseline over 10 a superscript negative 4 baseline b superscript negative 10 baseline endfraction in simplified form? assume a not-equals 0, b not-equals 0.

Answer 1

The quotient for the given exponential expression (-8a⁸b⁻²)/(10a⁻⁴b⁻¹⁰) is (-4/5)(a¹²b⁸).

Exponents are of the form aˣ, read as "a to the power of x", and signify the product of a multiplied by itself x number of times.

In the question, we are given an exponential expression (-8a⁸b⁻²)/(10a⁻⁴b⁻¹⁰) and are asked to find the quotient of it.

To find the quotient, we will try to simplify the equation using the laws of exponents in the following way:-

(-8a⁸b⁻²)/(10a⁻⁴b⁻¹⁰),

= (-4/5)(a⁽⁸ ⁻ ⁽⁻⁴⁾⁾b⁽⁻² ⁻ ⁽⁻¹⁰⁾⁾) {Using the law of exponent: $\frac{x^{a} }{x^{b} } =x^{(a-b)}$ }

= (-4/5)(a¹²b⁸).

Therefore, the quotient for the given exponential expression (-8a⁸b⁻²)/(10a⁻⁴b⁻¹⁰) is (-4/5)(a¹²b⁸).

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