Question

what is the radius of the 5th orbital in hydrogen?

Answer 1

Answer: 1.32 x 10^-9 m

Explanation:

The formula for the radius of nth orbital is:

$r_{n}=\frac{n^{2}}{Z} \times 0.528 \text { Angstorms }$

For hydrogen, Z= 1, so we have:

$\begin{aligned}r_{n} &=5^{2} \times 0.528 \text { Angstorm } \\&=13.2 \text { Angstorms } \\&=13.2 \times 10^{-10} \mathrm{~m} \\&=1.32 \times 10^{-9} \mathrm{~m}\end{aligned}$