The percentage of men is more than 72 inches tall will be 0.15866.
The z-score is a statistical evaluation of a value's correlation to the mean of a collection of values, expressed in terms of standard deviation.
The z-score is given as
z = (x – μ) / σ
Where μ is the mean, σ is the standard deviation, and x is the sample.
Suppose the mean height for men is 70 inches, with a standard deviation of 2 inches.
Then the percentage of men are more than 72 inches tall will be
z = (72 – 70) / 2
z = 1
The percentage of men is more than 72 inches tall will be
P(x > 72) = P(z > 1)
P(x > 72) = 1 – P(x < 72)
P(x > 72) = 1 – 0.84134
P(x > 72) = 0.15866
Thun, the percentage of men are more than 72 inches tall will be 0.15866.
More about the z-score link is given below.
https://brainly.com/question/15016913
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