Answer:
[tex]\huge\boxed{\sf 20z\³ + 24z\² - 5z - 6}[/tex]
Step-by-step explanation:
= (5z + 6)(2z + 1)(2x - 1)
= (5z + 6)[(2z)² - (1)²]
= (5z + 6)(4z² - 1)
Distributing
= 5z (4z² - 1) + 6(4z² - 1)
= 20z³ - 5z + 24z² - 6
Arrange
= 20z³ + 24z² - 5z - 6
[tex]\rule[225]{225}{2}[/tex]