Question

Find the mass of a sample of water if its temperature dropped 24.8 °C when it lost 870 J of
heat. (Remember that specific heat capacity of water 4200 J/kg °C)

Answer 1

Answer:

8.35 × $10^{-3}$ kg

Explanation:

Remember the formula for heat:

$Q=mc\Delta T$

You just need to solve for m, doing so you're left with:

$m=\dfrac{Q}{c\Delta T}$

Replace the variables with numbers and that's it.