Question

Find the equation of the line that
is perpendicular to y = -8x + 2
and contains the point (-4,1).

Answer 1

Answer:

Step-by-step explanation:

slope of line ⊥ to y=-8x+2

is -1/-8=1/8

eq. of line with slope 1/8 thro' (-4,1) is

y-1=1/8  (x+4)

8y-8=x+4

8y=x+4+8

8y=x+12

y=1/8 x+12/8

or

y=1/8 x+3/2