These figures are similar . The perimeter and area of one are given. The perimeter of the other is also given. Find its area and round to the nearest tenth . imeter = 20cm; Area = 18.6c * m ^ 2 Perimeter ater = 28cm; Area=[ ? ] cm^ 2

Answer:
≈ 36.5 cm²
Step-by-step explanation:
given 2 similar figures with ratio of perimeters = a : b , then
ratio of areas = a² : b²
ratio of perimeters = 20 : 28 = 5 : 7 , then
ratio of areas = 5² : 7² = 25 : 49
let x be the required area then by proportion
[tex]\frac{18.6}{x}[/tex] = [tex]\frac{25}{49}[/tex] ( cross- multiply )
25x = 911.4 ( divide both sides by 25 )
x = 36.456
then area of shape is approx 36.5 cm² ( to the nearest tenth )