Answer:
[tex]y=-4; y=28[/tex]
Step-by-step explanation:
The way I like to think about it, with absolute value meaning the distance is
"find which number are 16 apart from 12". Which means 28 (to the right) or -4 (to the left).
More formally, applying the definition of absolute value,
[tex]|y-12|=16 \leftrightarrow y-12=\pm16\\y-12=-16 \rightarrow y=-4\\y-12=+16 \rightarrow y=28[/tex]
