Question

Find the equation of the line in slope-intercept form containing the points (6, -1) and (-3, 2).

Answer 1

$\quad \huge \quad \quad \boxed{ \tt \:Answer }$

$\qquad \tt \rightarrow \: y= - \cfrac{x}{ 3} + 1$

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$\large \tt Solution \: :$

Equation of line (two point form) :

$\qquad \tt \rightarrow \: (y - y_1) = \cfrac{y _1- y_2}{ x_1 - x_2} (x - x_1)$

$\qquad \tt \rightarrow \: (y - 2) = \cfrac{2 - ( - 1)}{ - 3 - 6} (x - ( - 3))$

$\qquad \tt \rightarrow \: (y - 2) = \cfrac{2 + 1}{ - 9} (x + 3)$

$\qquad \tt \rightarrow \: (y - 2) = - \cfrac{3}{ 9} (x + 3)$

$\qquad \tt \rightarrow \: (y - 2) = - \cfrac{1}{ 3} (x + 3)$

$\qquad \tt \rightarrow \: y - 2= - \cfrac{x}{ 3} - \cfrac{3}{3}$

$\qquad \tt \rightarrow \: y = - \cfrac{x}{ 3} - 1 \cfrac{}{} + 2$

$\qquad \tt \rightarrow \: y = - \cfrac{x}{ 3} + 1$

Answered by : ❝ AǫᴜᴀWɪᴢ ❞